Tuesday, 9 August 2016
LESSON NOTE ON CHECK ON CLOSED TRAVERSE
LESSON NOTE ON CHECK ON OPEN TRAVERSE
LESSON NOTE ON MEHODS OF TRAVERSING
LESSON NOTE ON CROSS-STAFF AND OPTICAL SQUARE
- Open
- French
- Adjustable
LESSON NOTE ON PROCEDURE OF PLOTTING
5. A suitable position for the base line is selected on the sheet so that the whole area along with all the objects it contains can be drawn within the space available in the map.
Lesson Note On The importance of geodetic control in the construction process
The purpose of construction guidance observations Geodetic observations are quite often required during the construction of the engineering structures. The purpose of these observations is either the geometric guidance of the construction or the control of the geometrical quality of the built structures. In both cases surveyors are required to compare the ’as built’ status of the structure with the geometric position and dimensions of the structures on the plans. Construction guidance observations are a part of the construction activities. These observations are carried out continuously during the construction process. The purpose of these observations is to quantify the discrepancies between the built structures and the planned positions and dimensions, thus these discrepancies can be corrected for by applying ’construction/assembly corrections’. Continuous guidance observations are required for example in the case of the construction of reinforced concrete structures using sliding formworks. Let’s imagine that the chimney is being constructed, that has a circular cross‐section.
The purpose of the construction guidance observations is to determine the radius and the center of the cross‐section of the built part. The discrepancies between the ’constructed’ cross‐ sections and the planned cross‐sections provide the geometrical correction for the placement of the sliding formwork. These corrections show not only the correction of the center line, but also the correction of the radius of the structure. Thus both the position of the sliding formwork and the dimension of the formwork can be corrected based on the construction guidance observations. In many cases the purpose of construction guidance observations is to adjust the position and the orientation of structural elements (for example: pillars). These adjustments are done with an iterative procedure. Firstly the structural element is placed approximately to the correct place and it is oriented approximately in the correct direction. Afterwards surveyors measure the exact position and orientation of the element and compute the required corrections to meet the planned position and orientation values. Based on these corrections, construction workers can adjust the placement and the orientation of the structural element. Unfortunately – mainly due to the large size and weight of these structures, this adjustment can not be done in a single step. Thus the new discrepancies in position and orientation must be quantified by the surveyor again, and new correction values are computed. Usually the correction values have a decreasing trend, thus the position and the orientation of the structure should converge to its planned position and orientation. This iterative process is done until the computed correction values are below the given tolerance. Construction control observations are done after the construction process is finished. In this case the purpose of the observations is the determination of the geometric error of the construction. The final approval of the construction usually depends on the results of these construction control observations. In some cases, when the construction process is separated into different individual steps, the results of the construction control observations are taken into consideration during the planning of the next construction step. Such an example can be the construction of the nuclear power plant in Paks, when the small geometric error of the construction of the buildings was taken into consideration in the planning of the technological facilities. In some cases the documentation of geometric construction error helps to determine the cause of malfunctioning structures. It is also important to mention that the positioning observations of the entire structures are usually distinguished from the positioning and dimensional observations of the structural elements. This is because of the fact that – in most cases – a lower accuracy is required for the positioning and the orientation of the entire structure compared to the positioning and the orientation of the structural elements. Imagine that a large hall can be misplaced by several centimeters without any serious consequences, but the misplacement of pillars inside the building by the same amount would lead to the failure of the structure.
LESSON NOTE ON SPHERICAL TRIANGLE
SOME TERMS USED IN LEVELLING OPERATIONS
1. Bench mark (BM): it is a fixed point on the earth’s surface whose level above ordance
datum is known.
2. Ordnance Datum (OD): it is the mean sea level to which all other levels are related.
3. Back sight (BS): is the first sight taken after the level has been set up. A sight taken to a
point whose height is known or can be calculated.
4. Foresight (FS): The last sight taken. A sight taken to a point whose height is required to
carry on the line of level.
5. Intermediate Sight (IS): it is any other sight taken.
6. Reduced Level (RL): calculated level of a point above or below the datum.
7. Height of Instrument (HI): The height of the line of collimation above the datum.
8. Line of Collimation (LM): It is an imaginary horizontal line drawn between two points.
9. Rise and fall: The difference is height or is level between two is referred to as a rise or fall.
10. Change Point (CP): the point at which both a foresight and then a back sight are taken.
LEVELING INSTRUMENTS
These include:
. A Level e.g. theodolite, transit dumpy level(automatic level),e.t.c.
. A staff
. Devices for angle measurements e.g. graphometer, magnetic compass, prismatic compass,
orientation compass
. Chain or tape
. Pegs, arrows and ranging poles
Sunday, 7 August 2016
LESSON NOTE ON INTRODUCTION TO SPHERICAL TRIANGLE
Solution of triangles Solution of triangles, is the main trigonometric problem of finding the characteristics of a triangle (angles and lengths of sides), when some of these are known. The triangle can be located on a plane or on a sphere. Applications requiring triangle solutions include geodesy, astronomy, construction, and navigation.
Solving plane triangles Edit Standard notation for a triangle A general form triangle has six main characteristics (see picture): three linear (side lengths a, b, c) and three angular (α, β, γ). The classical plane trigonometry problem is to specify three of the six characteristics and determine the other three. A triangle can be uniquely determined in this sense when given any of the following:[1][2] Three sides (SSS) Two sides and the included angle (SAS) Two sides and an angle not included between them (SSA), if the side length adjacent to the angle is shorter than the other side length. A side and the two angles adjacent to it (ASA) A side, the angle opposite to it and an angle adjacent to it (AAS).
Three angles (AAA) on the sphere (but not in the plane). For all cases in the plane, at least one of the side lengths must be specified. If only the angles are given, the side lengths cannot be determined, because any similar triangle is a solution. Main theorems Edit  Overview of particular steps and tools used when solving plane triangles The standard method of solving the problem is to use fundamental relations. Law of cosines {\displaystyle a^{2}=b^{2}+c^{2}-2bc\cos \alpha } {\displaystyle b^{2}=a^{2}+c^{2}-2ac\cos \beta } {\displaystyle c^{2}=a^{2}+b^{2}-2ab\cos \gamma } Law of sines {\displaystyle {\frac {a}{\sin \alpha }}={\frac {b}{\sin \beta }}={\frac {c}{\sin \gamma }}} Sum of angles {\displaystyle \alpha +\beta +\gamma =180^{\circ }} Law of tangents {\displaystyle {\frac {a-b}{a+b}}={\frac {\mathrm {tan} [{\frac {1}{2}}(\alpha -\beta )]}{\mathrm {tan} [{\frac {1}{2}}(\alpha +\beta )]}}.} There are other (sometimes practically useful) universal relations: the law of cotangents and Mollweide's formula. Notes Edit To find an unknown angle, the law of cosines is safer than the law of sines. The reason is that the value of sine for the angle of the triangle does not uniquely determine this angle. For example, if sin β = 0.5, the angle β can equal either 30° or 150°. Using the law of cosines avoids this problem: within the interval from 0° to 180° the cosine value unambiguously determines its angle. On the other hand, if the angle is small (or close to 180°), then it is more robust numerically to determine it from its sine than its cosine because the arc-cosine function has a divergent derivative at 1 (or −1). We assume that the relative position of specified characteristics is known. If not, the mirror reflection of the triangle will also be a solution. For example, three side lengths uniquely define either a triangle or its reflection.  Three sides given Three sides given (SSS) Edit Let three side lengths a, b, c be specified. To find the angles α, β, the law of cosines can be used:[3] {\displaystyle \alpha =\arccos {\frac {b^{2}+c^{2}-a^{2}}{2bc}}} {\displaystyle \beta =\arccos {\frac {a^{2}+c^{2}-b^{2}}{2ac}}.} Then angle γ = 180° − α − β. Some sources recommend to find angle β from the law of sines but (as Note 1 above states) there is a risk of confusing an acute angle value with an obtuse one. Another method of calculating the angles from known sides is to apply the law of cotangents.  Two sides and the included angle given Two sides and the included angle given (SAS) Edit Here the lengths of sides a, b and the angle γ between these sides are known. The third side can be determined from the law of cosines:[4] {\displaystyle c={\sqrt {a^{2}+b^{2}-2ab\cos \gamma }}.} Now we use law of cosines to find the second angle: {\displaystyle \alpha =\arccos {\frac {b^{2}+c^{2}-a^{2}}{2bc}}.} Finally, β = 180° − α − γ.  Two sides and a non-included angle given Two sides and non-included angle given (SSA) Edit This case is not solvable in all cases; a solution is guaranteed to be unique only if the side length adjacent to the angle is shorter than the other side length. Assume that two sides b, c and the angle β are known. The equation for the angle γ can be implied from the law of sines:[5] {\displaystyle \sin \gamma ={\frac {c}{b}}\sin \beta .} We denote further D = c / b sin β (the equation's right side). There are four possible cases: If D > 1, no such triangle exists because the side b does not reach line BC. For the same reason a solution does not exist if the angle β ≥ 90° and b ≤ c. If D = 1, a unique solution exists: γ = 90°, i.e., the triangle is right-angled.  Two solutions for the triangle If D < 1 two alternatives are possible. If b < c, the angle γ may be acute: γ = arcsin D or obtuse: γ′ = 180° - γ. The picture on right shows the point C, the side b and the angle γ as the first solution, and the point C′, side b′ and the angle γ′ as the second solution. If b ≥ c then β ≥ γ (the larger side corresponds to a larger angle). Since no triangle can have two obtuse angles, γ is an acute angle and the solution γ = arcsin D is unique. Once γ is obtained, the third angle α = 180° − β − γ. The third side can then be found from the law of sines: {\displaystyle a=b\ {\frac {\sin \alpha }{\sin \beta }}}  One side and two adjacent angles given A side and two adjacent angles given (ASA) Edit The known characteristics are the side c and the angles α, β. The third angle γ = 180° − α − β. Two unknown side can be calculated from the law of sines:[6] {\displaystyle a=c\ {\frac {\sin \alpha }{\sin \gamma }};\quad b=c\ {\frac {\sin \beta }{\sin \gamma }}.} A side, one adjacent angle and the opposite angle given (AAS) Edit The procedure for solving an AAS triangle is same as that for an ASA triangle: First, find the third angle by using the angle sum property of a triangle, then find the other two sides using the law of sines. 
LESSON NOTE ON INTRODUCTION TO SPHERICAL TRIANGLE
Solution of triangles Solution of triangles, is the main trigonometric problem of finding the characteristics of a triangle (angles and lengths of sides), when some of these are known. The triangle can be located on a plane or on a sphere. Applications requiring triangle solutions include geodesy, astronomy, construction, and navigation.
Solving plane triangles Edit Standard notation for a triangle A general form triangle has six main characteristics (see picture): three linear (side lengths a, b, c) and three angular (α, β, γ). The classical plane trigonometry problem is to specify three of the six characteristics and determine the other three. A triangle can be uniquely determined in this sense when given any of the following:[1][2] Three sides (SSS) Two sides and the included angle (SAS) Two sides and an angle not included between them (SSA), if the side length adjacent to the angle is shorter than the other side length. A side and the two angles adjacent to it (ASA) A side, the angle opposite to it and an angle adjacent to it (AAS).
Three angles (AAA) on the sphere (but not in the plane). For all cases in the plane, at least one of the side lengths must be specified. If only the angles are given, the side lengths cannot be determined, because any similar triangle is a solution. Main theorems Edit  Overview of particular steps and tools used when solving plane triangles The standard method of solving the problem is to use fundamental relations. Law of cosines {\displaystyle a^{2}=b^{2}+c^{2}-2bc\cos \alpha } {\displaystyle b^{2}=a^{2}+c^{2}-2ac\cos \beta } {\displaystyle c^{2}=a^{2}+b^{2}-2ab\cos \gamma } Law of sines {\displaystyle {\frac {a}{\sin \alpha }}={\frac {b}{\sin \beta }}={\frac {c}{\sin \gamma }}} Sum of angles {\displaystyle \alpha +\beta +\gamma =180^{\circ }} Law of tangents {\displaystyle {\frac {a-b}{a+b}}={\frac {\mathrm {tan} [{\frac {1}{2}}(\alpha -\beta )]}{\mathrm {tan} [{\frac {1}{2}}(\alpha +\beta )]}}.} There are other (sometimes practically useful) universal relations: the law of cotangents and Mollweide's formula. Notes Edit To find an unknown angle, the law of cosines is safer than the law of sines. The reason is that the value of sine for the angle of the triangle does not uniquely determine this angle. For example, if sin β = 0.5, the angle β can equal either 30° or 150°. Using the law of cosines avoids this problem: within the interval from 0° to 180° the cosine value unambiguously determines its angle. On the other hand, if the angle is small (or close to 180°), then it is more robust numerically to determine it from its sine than its cosine because the arc-cosine function has a divergent derivative at 1 (or −1). We assume that the relative position of specified characteristics is known. If not, the mirror reflection of the triangle will also be a solution. For example, three side lengths uniquely define either a triangle or its reflection.  Three sides given Three sides given (SSS) Edit Let three side lengths a, b, c be specified. To find the angles α, β, the law of cosines can be used:[3] {\displaystyle \alpha =\arccos {\frac {b^{2}+c^{2}-a^{2}}{2bc}}} {\displaystyle \beta =\arccos {\frac {a^{2}+c^{2}-b^{2}}{2ac}}.} Then angle γ = 180° − α − β. Some sources recommend to find angle β from the law of sines but (as Note 1 above states) there is a risk of confusing an acute angle value with an obtuse one. Another method of calculating the angles from known sides is to apply the law of cotangents.  Two sides and the included angle given Two sides and the included angle given (SAS) Edit Here the lengths of sides a, b and the angle γ between these sides are known. The third side can be determined from the law of cosines:[4] {\displaystyle c={\sqrt {a^{2}+b^{2}-2ab\cos \gamma }}.} Now we use law of cosines to find the second angle: {\displaystyle \alpha =\arccos {\frac {b^{2}+c^{2}-a^{2}}{2bc}}.} Finally, β = 180° − α − γ.  Two sides and a non-included angle given Two sides and non-included angle given (SSA) Edit This case is not solvable in all cases; a solution is guaranteed to be unique only if the side length adjacent to the angle is shorter than the other side length. Assume that two sides b, c and the angle β are known. The equation for the angle γ can be implied from the law of sines:[5] {\displaystyle \sin \gamma ={\frac {c}{b}}\sin \beta .} We denote further D = c / b sin β (the equation's right side). There are four possible cases: If D > 1, no such triangle exists because the side b does not reach line BC. For the same reason a solution does not exist if the angle β ≥ 90° and b ≤ c. If D = 1, a unique solution exists: γ = 90°, i.e., the triangle is right-angled.  Two solutions for the triangle If D < 1 two alternatives are possible. If b < c, the angle γ may be acute: γ = arcsin D or obtuse: γ′ = 180° - γ. The picture on right shows the point C, the side b and the angle γ as the first solution, and the point C′, side b′ and the angle γ′ as the second solution. If b ≥ c then β ≥ γ (the larger side corresponds to a larger angle). Since no triangle can have two obtuse angles, γ is an acute angle and the solution γ = arcsin D is unique. Once γ is obtained, the third angle α = 180° − β − γ. The third side can then be found from the law of sines: {\displaystyle a=b\ {\frac {\sin \alpha }{\sin \beta }}}  One side and two adjacent angles given A side and two adjacent angles given (ASA) Edit The known characteristics are the side c and the angles α, β. The third angle γ = 180° − α − β. Two unknown side can be calculated from the law of sines:[6] {\displaystyle a=c\ {\frac {\sin \alpha }{\sin \gamma }};\quad b=c\ {\frac {\sin \beta }{\sin \gamma }}.} A side, one adjacent angle and the opposite angle given (AAS) Edit The procedure for solving an AAS triangle is same as that for an ASA triangle: First, find the third angle by using the angle sum property of a triangle, then find the other two sides using the law of sines.